Base | Representation |
---|---|
bin | 10000011110100010111… |
… | …101000011100101010111 |
3 | 11000020200122121202011020 |
4 | 100132202331003211113 |
5 | 122022432420011203 |
6 | 2224102015412223 |
7 | 144543463600461 |
oct | 20364275034527 |
9 | 4006618552136 |
10 | 1132310313303 |
11 | 3a723471a664 |
12 | 163548524073 |
13 | 82a129b6860 |
14 | 3cb386a7131 |
15 | 1e6c2337153 |
hex | 107a2f43957 |
1132310313303 has 16 divisors (see below), whose sum is σ = 1642643145696. Its totient is φ = 689622773760.
The previous prime is 1132310313287. The next prime is 1132310313367. The reversal of 1132310313303 is 3033130132311.
It is not a de Polignac number, because 1132310313303 - 24 = 1132310313287 is a prime.
It is a super-2 number, since 2×11323103133032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1132310313383) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 149653938 + ... + 149661503.
It is an arithmetic number, because the mean of its divisors is an integer number (102665196606).
Almost surely, 21132310313303 is an apocalyptic number.
1132310313303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1132310313303 is a deficient number, since it is larger than the sum of its proper divisors (510332832393).
1132310313303 is a wasteful number, since it uses less digits than its factorization.
1132310313303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 299315554.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 1132310313303 its reverse (3033130132311), we get a palindrome (4165440445614).
The spelling of 1132310313303 in words is "one trillion, one hundred thirty-two billion, three hundred ten million, three hundred thirteen thousand, three hundred three".
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