113231041432441 has 4 divisors (see below), whose sum is σ = 116291339849572. Its totient is φ = 110170743015312.

The previous prime is 113231041432433. The next prime is 113231041432451. The reversal of 113231041432441 is 144234140132311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 71839253446416 + 41391787986025 = 8475804^2 + 6433645^2 .

It is a cyclic number.

It is not a de Polignac number, because 113231041432441 - 2³ = 113231041432433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113231041432397 and 113231041432406.

It is not an unprimeable number, because it can be changed into a prime (113231041432451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1530149208510 + ... + 1530149208583.

It is an arithmetic number, because the mean of its divisors is an integer number (29072834962393).

Almost surely, 2^{113231041432441} is an apocalyptic number.

It is an amenable number.

113231041432441 is a deficient number, since it is larger than the sum of its proper divisors (3060298417131).

113231041432441 is an equidigital number, since it uses as much as digits as its factorization.

113231041432441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3060298417130.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 113231041432441 its reverse (144234140132311), we get a palindrome (257465181564752).

The spelling of 113231041432441 in words is "one hundred thirteen trillion, two hundred thirty-one billion, forty-one million, four hundred thirty-two thousand, four hundred forty-one".