Base | Representation |
---|---|
bin | 110100101110100011… |
… | …0011010110000100101 |
3 | 101211021021022112111022 |
4 | 1221131012122300211 |
5 | 3323344131111003 |
6 | 124003451420525 |
7 | 11115654403466 |
oct | 1513506326045 |
9 | 354237275438 |
10 | 113231113253 |
11 | 44026014345 |
12 | 19b40a54745 |
13 | a8a6a4033b |
14 | 56a238ad6d |
15 | 2e2aade738 |
hex | 1a5d19ac25 |
113231113253 has 2 divisors, whose sum is σ = 113231113254. Its totient is φ = 113231113252.
The previous prime is 113231113213. The next prime is 113231113271. The reversal of 113231113253 is 352311132311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 65791224004 + 47439889249 = 256498^2 + 217807^2 .
It is an emirp because it is prime and its reverse (352311132311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113231113253 - 210 = 113231112229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113231113213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56615556626 + 56615556627.
It is an arithmetic number, because the mean of its divisors is an integer number (56615556627).
Almost surely, 2113231113253 is an apocalyptic number.
It is an amenable number.
113231113253 is a deficient number, since it is larger than the sum of its proper divisors (1).
113231113253 is an equidigital number, since it uses as much as digits as its factorization.
113231113253 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1620, while the sum is 26.
Adding to 113231113253 its reverse (352311132311), we get a palindrome (465542245564).
The spelling of 113231113253 in words is "one hundred thirteen billion, two hundred thirty-one million, one hundred thirteen thousand, two hundred fifty-three".
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