Base | Representation |
---|---|
bin | 1010010011000101111000… |
… | …0001110101010011001111 |
3 | 1111002110221002121222002121 |
4 | 2210301132001311103033 |
5 | 2441004213000043043 |
6 | 40025433204433411 |
7 | 2246032153162552 |
oct | 244613601652317 |
9 | 44073832558077 |
10 | 11323111331023 |
11 | 3676117176288 |
12 | 132a5b30a8867 |
13 | 6419c33c1c5b |
14 | 2b2081ca6699 |
15 | 149817d19ded |
hex | a4c5e0754cf |
11323111331023 has 2 divisors, whose sum is σ = 11323111331024. Its totient is φ = 11323111331022.
The previous prime is 11323111330997. The next prime is 11323111331033. The reversal of 11323111331023 is 32013311132311.
11323111331023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11323111331023 - 221 = 11323109233871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11323111331033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661555665511 + 5661555665512.
It is an arithmetic number, because the mean of its divisors is an integer number (5661555665512).
Almost surely, 211323111331023 is an apocalyptic number.
11323111331023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323111331023 is an equidigital number, since it uses as much as digits as its factorization.
11323111331023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 11323111331023 its reverse (32013311132311), we get a palindrome (43336422463334).
The spelling of 11323111331023 in words is "eleven trillion, three hundred twenty-three billion, one hundred eleven million, three hundred thirty-one thousand, twenty-three".
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