11323300221133 has 4 divisors (see below), whose sum is σ = 11323824785280. Its totient is φ = 11322775656988.

The previous prime is 11323300221119. The next prime is 11323300221151. The reversal of 11323300221133 is 33112200332311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11323300221133 - 2¹³ = 11323300212941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11323300221098 and 11323300221107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11323300221433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 262249693 + ... + 262292866.

It is an arithmetic number, because the mean of its divisors is an integer number (2830956196320).

Almost surely, 2^{11323300221133} is an apocalyptic number.

It is an amenable number.

11323300221133 is a deficient number, since it is larger than the sum of its proper divisors (524564147).

11323300221133 is an equidigital number, since it uses as much as digits as its factorization.

11323300221133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 524564146.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 11323300221133 its reverse (33112200332311), we get a palindrome (44435500553444).

The spelling of 11323300221133 in words is "eleven trillion, three hundred twenty-three billion, three hundred million, two hundred twenty-one thousand, one hundred thirty-three".