11323320222031 has 2 divisors, whose sum is σ = 11323320222032. Its totient is φ = 11323320222030.

The previous prime is 11323320222013. The next prime is 11323320222073. The reversal of 11323320222031 is 13022202332311.

11323320222031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (11323320222013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (13022202332311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11323320222031 - 2⁵ = 11323320221999 is a prime.

It is a super-2 number, since 2×11323320222031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11323320221987 and 11323320222005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11323320222931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661660111015 + 5661660111016.

It is an arithmetic number, because the mean of its divisors is an integer number (5661660111016).

Almost surely, 2^{11323320222031} is an apocalyptic number.

11323320222031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11323320222031 is an equidigital number, since it uses as much as digits as its factorization.

11323320222031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 11323320222031 its reverse (13022202332311), we get a palindrome (24345522554342).

The spelling of 11323320222031 in words is "eleven trillion, three hundred twenty-three billion, three hundred twenty million, two hundred twenty-two thousand, thirty-one".