Base | Representation |
---|---|
bin | 1010010011000110101110… |
… | …1010100110010000001111 |
3 | 1111002111112001010201002021 |
4 | 2210301223222212100033 |
5 | 2441010200032333403 |
6 | 40025512020311011 |
7 | 2246040631646203 |
oct | 244615352462017 |
9 | 44074461121067 |
10 | 11323340121103 |
11 | 367622433269a |
12 | 132a657842467 |
13 | 641a2b9195ba |
14 | 2b20a4420b03 |
15 | 14982ce5e8bd |
hex | a4c6baa640f |
11323340121103 has 2 divisors, whose sum is σ = 11323340121104. Its totient is φ = 11323340121102.
The previous prime is 11323340121029. The next prime is 11323340121109. The reversal of 11323340121103 is 30112104332311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11323340121103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11323340121109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661670060551 + 5661670060552.
It is an arithmetic number, because the mean of its divisors is an integer number (5661670060552).
Almost surely, 211323340121103 is an apocalyptic number.
11323340121103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323340121103 is an equidigital number, since it uses as much as digits as its factorization.
11323340121103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 11323340121103 its reverse (30112104332311), we get a palindrome (41435444453414).
The spelling of 11323340121103 in words is "eleven trillion, three hundred twenty-three billion, three hundred forty million, one hundred twenty-one thousand, one hundred three".
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