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113236571341 = 311364104731
BaseRepresentation
bin110100101110101101…
…1001111010011001101
3101211021122120211120201
41221131123033103031
53323402030240331
6124004204413501
711116051655335
oct1513533172315
9354248524521
10113236571341
1144029102063
1219b42847291
13a8a7c0178a
1456a2dac0c5
152e2b31ba61
hex1a5d6cf4cd

113236571341 has 4 divisors (see below), whose sum is σ = 113600676384. Its totient is φ = 112872466300.

The previous prime is 113236571249. The next prime is 113236571351. The reversal of 113236571341 is 143175632311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 143175632311 = 724931975027.

It is a cyclic number.

It is not a de Polignac number, because 113236571341 - 215 = 113236538573 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113236571341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113236571351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182052055 + ... + 182052676.

It is an arithmetic number, because the mean of its divisors is an integer number (28400169096).

Almost surely, 2113236571341 is an apocalyptic number.

It is an amenable number.

113236571341 is a deficient number, since it is larger than the sum of its proper divisors (364105043).

113236571341 is an equidigital number, since it uses as much as digits as its factorization.

113236571341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 364105042.

The product of its digits is 45360, while the sum is 37.

The spelling of 113236571341 in words is "one hundred thirteen billion, two hundred thirty-six million, five hundred seventy-one thousand, three hundred forty-one".

Divisors: 1 311 364104731 113236571341