Base | Representation |
---|---|
bin | 10101000101111011… |
… | …01000111100111111 |
3 | 1002020012002220120121 |
4 | 22202331220330333 |
5 | 141142421031421 |
6 | 5111400355411 |
7 | 550422300262 |
oct | 124275507477 |
9 | 32205086517 |
10 | 11324002111 |
11 | 4891116434 |
12 | 2240475b67 |
13 | 10b60aa386 |
14 | 795d30cd9 |
15 | 46423ed41 |
hex | 2a2f68f3f |
11324002111 has 4 divisors (see below), whose sum is σ = 11324383072. Its totient is φ = 11323621152.
The previous prime is 11324002097. The next prime is 11324002153. The reversal of 11324002111 is 11120042311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11324002111 is a prime.
It is a super-3 number, since 3×113240021113 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11324002171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141735 + ... + 206728.
It is an arithmetic number, because the mean of its divisors is an integer number (2831095768).
Almost surely, 211324002111 is an apocalyptic number.
11324002111 is a deficient number, since it is larger than the sum of its proper divisors (380961).
11324002111 is an equidigital number, since it uses as much as digits as its factorization.
11324002111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 380960.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 11324002111 its reverse (11120042311), we get a palindrome (22444044422).
The spelling of 11324002111 in words is "eleven billion, three hundred twenty-four million, two thousand, one hundred eleven".
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