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113240110141 is a prime number
BaseRepresentation
bin110100101110110100…
…0101111010000111101
3101211021220020121220101
41221131220233100331
53323403432011031
6124004412321101
711116124024464
oct1513550572075
9354256217811
10113240110141
11440300a9894
1219b43a73191
13a8a8870442
1456a364d9db
152e2b7ba361
hex1a5da2f43d

113240110141 has 2 divisors, whose sum is σ = 113240110142. Its totient is φ = 113240110140.

The previous prime is 113240110091. The next prime is 113240110153. The reversal of 113240110141 is 141011042311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86772074041 + 26468036100 = 294571^2 + 162690^2 .

It is an emirp because it is prime and its reverse (141011042311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113240110141 - 29 = 113240109629 is a prime.

It is a super-2 number, since 2×1132401101412 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113240116141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56620055070 + 56620055071.

It is an arithmetic number, because the mean of its divisors is an integer number (56620055071).

Almost surely, 2113240110141 is an apocalyptic number.

It is an amenable number.

113240110141 is a deficient number, since it is larger than the sum of its proper divisors (1).

113240110141 is an equidigital number, since it uses as much as digits as its factorization.

113240110141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 113240110141 its reverse (141011042311), we get a palindrome (254251152452).

The spelling of 113240110141 in words is "one hundred thirteen billion, two hundred forty million, one hundred ten thousand, one hundred forty-one".