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113241220034 = 2459712316861
BaseRepresentation
bin110100101110110110…
…0111110001111000010
3101211021222100000101112
41221131230332033002
53323404223020114
6124004452203322
711116136326355
oct1513554761702
9354258300345
10113241220034
1144030797758
1219b44309542
13a8a8b6b697
1456a385c29c
152e2b93913e
hex1a5db3e3c2

113241220034 has 8 divisors (see below), whose sum is σ = 169898794428. Its totient is φ = 56608288560.

The previous prime is 113241219979. The next prime is 113241220049. The reversal of 113241220034 is 430022142311.

It can be written as a sum of positive squares in 2 ways, for example, as 75077644009 + 38163576025 = 274003^2 + 195355^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1132412200342 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113241219991 and 113241220009.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6149237 + ... + 6167624.

Almost surely, 2113241220034 is an apocalyptic number.

113241220034 is a deficient number, since it is larger than the sum of its proper divisors (56657574394).

113241220034 is a wasteful number, since it uses less digits than its factorization.

113241220034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12321460.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 113241220034 its reverse (430022142311), we get a palindrome (543263362345).

The spelling of 113241220034 in words is "one hundred thirteen billion, two hundred forty-one million, two hundred twenty thousand, thirty-four".

Divisors: 1 2 4597 9194 12316861 24633722 56620610017 113241220034