Base | Representation |
---|---|
bin | 110100101110110110… |
… | …1010110101010001101 |
3 | 101211021222112002121211 |
4 | 1221131231112222031 |
5 | 3323404234220302 |
6 | 124004454254421 |
7 | 11116140224134 |
oct | 1513555265215 |
9 | 354258462554 |
10 | 113241320077 |
11 | 44030855936 |
12 | 19b44357411 |
13 | a8a8ba5092 |
14 | 56a388691b |
15 | 2e2b958ad7 |
hex | 1a5db56a8d |
113241320077 has 2 divisors, whose sum is σ = 113241320078. Its totient is φ = 113241320076.
The previous prime is 113241320041. The next prime is 113241320117. The reversal of 113241320077 is 770023142311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 102439043721 + 10802276356 = 320061^2 + 103934^2 .
It is a cyclic number.
It is not a de Polignac number, because 113241320077 - 215 = 113241287309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113241329077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56620660038 + 56620660039.
It is an arithmetic number, because the mean of its divisors is an integer number (56620660039).
Almost surely, 2113241320077 is an apocalyptic number.
It is an amenable number.
113241320077 is a deficient number, since it is larger than the sum of its proper divisors (1).
113241320077 is an equidigital number, since it uses as much as digits as its factorization.
113241320077 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7056, while the sum is 31.
Adding to 113241320077 its reverse (770023142311), we get a palindrome (883264462388).
The spelling of 113241320077 in words is "one hundred thirteen billion, two hundred forty-one million, three hundred twenty thousand, seventy-seven".
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