Base | Representation |
---|---|
bin | 110100101110110110… |
… | …1101101100101111101 |
3 | 101211021222200212110221 |
4 | 1221131231231211331 |
5 | 3323404300222023 |
6 | 124004500301341 |
7 | 11116141065040 |
oct | 1513555554575 |
9 | 354258625427 |
10 | 113241414013 |
11 | 4403090a472 |
12 | 19b443a1851 |
13 | a8a8c08a70 |
14 | 56a38acc57 |
15 | 2e2b97685d |
hex | 1a5db6d97d |
113241414013 has 16 divisors (see below), whose sum is σ = 139877234560. Its totient is φ = 89274125376.
The previous prime is 113241414007. The next prime is 113241414017. The reversal of 113241414013 is 310414142311.
It is a cyclic number.
It is not a de Polignac number, because 113241414013 - 25 = 113241413981 is a prime.
It is a super-3 number, since 3×1132414140133 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113241414017) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2221023 + ... + 2271436.
It is an arithmetic number, because the mean of its divisors is an integer number (8742327160).
Almost surely, 2113241414013 is an apocalyptic number.
113241414013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
113241414013 is a deficient number, since it is larger than the sum of its proper divisors (26635820547).
113241414013 is a wasteful number, since it uses less digits than its factorization.
113241414013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4492756.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 113241414013 its reverse (310414142311), we get a palindrome (423655556324).
The spelling of 113241414013 in words is "one hundred thirteen billion, two hundred forty-one million, four hundred fourteen thousand, thirteen".
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