11324143433 has 4 divisors (see below), whose sum is σ = 11410587408. Its totient is φ = 11237699460.

The previous prime is 11324143423. The next prime is 11324143477. The reversal of 11324143433 is 33434142311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11324143433 - 2²² = 11319949129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11324143396 and 11324143405.

It is not an unprimeable number, because it can be changed into a prime (11324143423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43221791 + ... + 43222052.

It is an arithmetic number, because the mean of its divisors is an integer number (2852646852).

Almost surely, 2^11324143433 is an apocalyptic number.

It is an amenable number.

11324143433 is a deficient number, since it is larger than the sum of its proper divisors (86443975).

11324143433 is an equidigital number, since it uses as much as digits as its factorization.

11324143433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 86443974.

The product of its digits is 10368, while the sum is 29.

Adding to 11324143433 its reverse (33434142311), we get a palindrome (44758285744).

The spelling of 11324143433 in words is "eleven billion, three hundred twenty-four million, one hundred forty-three thousand, four hundred thirty-three".