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113241510658 = 256620755329
BaseRepresentation
bin110100101110110111…
…0000101001100000010
3101211021222212210001101
41221131232011030002
53323404311320113
6124004502325014
711116141646563
oct1513556051402
9354258783041
10113241510658
1144030976041
1219b4442976a
13a8a8c40a53
1456a38d616a
152e2b9952dd
hex1a5db85302

113241510658 has 4 divisors (see below), whose sum is σ = 169862265990. Its totient is φ = 56620755328.

The previous prime is 113241510623. The next prime is 113241510677. The reversal of 113241510658 is 856015142311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 71399580849 + 41841929809 = 267207^2 + 204553^2 .

It is a super-2 number, since 2×1132415106582 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28310377663 + ... + 28310377666.

Almost surely, 2113241510658 is an apocalyptic number.

113241510658 is a deficient number, since it is larger than the sum of its proper divisors (56620755332).

113241510658 is an equidigital number, since it uses as much as digits as its factorization.

113241510658 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56620755331.

The product of its (nonzero) digits is 28800, while the sum is 37.

Adding to 113241510658 its reverse (856015142311), we get a palindrome (969256652969).

The spelling of 113241510658 in words is "one hundred thirteen billion, two hundred forty-one million, five hundred ten thousand, six hundred fifty-eight".

Divisors: 1 2 56620755329 113241510658