Base | Representation |
---|---|
bin | 1010010011001010101011… |
… | …1010010111101011010111 |
3 | 1111002121020222210010112221 |
4 | 2210302222322113223113 |
5 | 2441014333203022221 |
6 | 40030205203323211 |
7 | 2246106135102664 |
oct | 244625272275327 |
9 | 44077228703487 |
10 | 11324401220311 |
11 | 3676719298193 |
12 | 132a8b3080507 |
13 | 641b6a6c9b5a |
14 | 2b2165314a6b |
15 | 1498911ae541 |
hex | a4caae97ad7 |
11324401220311 has 2 divisors, whose sum is σ = 11324401220312. Its totient is φ = 11324401220310.
The previous prime is 11324401220303. The next prime is 11324401220317. The reversal of 11324401220311 is 11302210442311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11324401220311 - 23 = 11324401220303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11324401220317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662200610155 + 5662200610156.
It is an arithmetic number, because the mean of its divisors is an integer number (5662200610156).
Almost surely, 211324401220311 is an apocalyptic number.
11324401220311 is a deficient number, since it is larger than the sum of its proper divisors (1).
11324401220311 is an equidigital number, since it uses as much as digits as its factorization.
11324401220311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 11324401220311 its reverse (11302210442311), we get a palindrome (22626611662622).
The spelling of 11324401220311 in words is "eleven trillion, three hundred twenty-four billion, four hundred one million, two hundred twenty thousand, three hundred eleven".
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