Base | Representation |
---|---|
bin | 10101000101111110… |
… | …10010001001101111 |
3 | 1002020012220210122201 |
4 | 22202333102021233 |
5 | 141143023324012 |
6 | 5111413522331 |
7 | 550426043446 |
oct | 124277221157 |
9 | 32205823581 |
10 | 11324433007 |
11 | 4891390148 |
12 | 22406433a7 |
13 | 10b61cb544 |
14 | 796003d5d |
15 | 4642c7857 |
hex | 2a2fd226f |
11324433007 has 8 divisors (see below), whose sum is σ = 11348774784. Its totient is φ = 11300115288.
The previous prime is 11324432971. The next prime is 11324433059. The reversal of 11324433007 is 70033442311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11324433007 - 211 = 11324430959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11324433077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1171998 + ... + 1181620.
It is an arithmetic number, because the mean of its divisors is an integer number (1418596848).
Almost surely, 211324433007 is an apocalyptic number.
11324433007 is a deficient number, since it is larger than the sum of its proper divisors (24341777).
11324433007 is an equidigital number, since it uses as much as digits as its factorization.
11324433007 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12029.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 11324433007 its reverse (70033442311), we get a palindrome (81357875318).
The spelling of 11324433007 in words is "eleven billion, three hundred twenty-four million, four hundred thirty-three thousand, seven".
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