1132444033 has 4 divisors (see below), whose sum is σ = 1294221760. Its totient is φ = 970666308.

The previous prime is 1132444021. The next prime is 1132444051. The reversal of 1132444033 is 3304442311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3304442311 = 71 ⋅46541441.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1132444033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1132443989 and 1132444007.

It is not an unprimeable number, because it can be changed into a prime (1132444063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80888853 + ... + 80888866.

It is an arithmetic number, because the mean of its divisors is an integer number (323555440).

Almost surely, 2^1132444033 is an apocalyptic number.

It is an amenable number.

1132444033 is a deficient number, since it is larger than the sum of its proper divisors (161777727).

1132444033 is an equidigital number, since it uses as much as digits as its factorization.

1132444033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 161777726.

The product of its (nonzero) digits is 3456, while the sum is 25.

The square root of 1132444033 is about 33651.8057910716. The cubic root of 1132444033 is about 1042.3308278264.

Adding to 1132444033 its reverse (3304442311), we get a palindrome (4436886344).

The spelling of 1132444033 in words is "one billion, one hundred thirty-two million, four hundred forty-four thousand, thirty-three".