Base | Representation |
---|---|
bin | 1010010011001010110101… |
… | …0011011000110101101111 |
3 | 1111002121100210021001221220 |
4 | 2210302231103120311233 |
5 | 2441014423440124403 |
6 | 40030213155154423 |
7 | 2246110133050623 |
oct | 244625523306557 |
9 | 44077323231856 |
10 | 11324441333103 |
11 | 36767399a5558 |
12 | 132a9045a5a13 |
13 | 641b75b02b32 |
14 | 2b216a797183 |
15 | 149894984953 |
hex | a4cad4d8d6f |
11324441333103 has 8 divisors (see below), whose sum is σ = 15099301844016. Its totient is φ = 7549604188800.
The previous prime is 11324441333071. The next prime is 11324441333111. The reversal of 11324441333103 is 30133314442311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11324441333103 - 25 = 11324441333071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11324441331103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4677688 + ... + 6673053.
It is an arithmetic number, because the mean of its divisors is an integer number (1887412730502).
Almost surely, 211324441333103 is an apocalyptic number.
11324441333103 is a deficient number, since it is larger than the sum of its proper divisors (3774860510913).
11324441333103 is a wasteful number, since it uses less digits than its factorization.
11324441333103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11683305.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 11324441333103 its reverse (30133314442311), we get a palindrome (41457755775414).
The spelling of 11324441333103 in words is "eleven trillion, three hundred twenty-four billion, four hundred forty-one million, three hundred thirty-three thousand, one hundred three".
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