Base | Representation |
---|---|
bin | 1010010011001010111000… |
… | …0100001101100110101111 |
3 | 1111002121101200100022221102 |
4 | 2210302232010031212233 |
5 | 2441014440224212033 |
6 | 40030214333353315 |
7 | 2246110346615615 |
oct | 244625604154657 |
9 | 44077350308842 |
10 | 11324454132143 |
11 | 3676746147679 |
12 | 132a90893883b |
13 | 641b78664729 |
14 | 2b216c3696b5 |
15 | 149895b61de8 |
hex | a4cae10d9af |
11324454132143 has 4 divisors (see below), whose sum is σ = 11405925025320. Its totient is φ = 11242983238968.
The previous prime is 11324454132127. The next prime is 11324454132157. The reversal of 11324454132143 is 34123145442311.
11324454132143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11324454132143 - 24 = 11324454132127 is a prime.
It is a super-2 number, since 2×113244541321432 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11324454132097 and 11324454132106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11324454182143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40735446380 + ... + 40735446657.
It is an arithmetic number, because the mean of its divisors is an integer number (2851481256330).
Almost surely, 211324454132143 is an apocalyptic number.
11324454132143 is a deficient number, since it is larger than the sum of its proper divisors (81470893177).
11324454132143 is an equidigital number, since it uses as much as digits as its factorization.
11324454132143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81470893176.
The product of its digits is 138240, while the sum is 38.
Adding to 11324454132143 its reverse (34123145442311), we get a palindrome (45447599574454).
The spelling of 11324454132143 in words is "eleven trillion, three hundred twenty-four billion, four hundred fifty-four million, one hundred thirty-two thousand, one hundred forty-three".
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