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113249993 is a prime number
BaseRepresentation
bin1101100000000…
…00111011001001
321220002200210012
412300000323021
5212442444433
615123201305
72543415623
oct660007311
9256080705
10113249993
1158a2143a
1231b16235
131a60273c
141107dc13
159e20848
hex6c00ec9

113249993 has 2 divisors, whose sum is σ = 113249994. Its totient is φ = 113249992.

The previous prime is 113249989. The next prime is 113250001. The reversal of 113249993 is 399942311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107163904 + 6086089 = 10352^2 + 2467^2 .

It is an emirp because it is prime and its reverse (399942311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113249993 - 22 = 113249989 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113249993.

It is not a weakly prime, because it can be changed into another prime (113243993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56624996 + 56624997.

It is an arithmetic number, because the mean of its divisors is an integer number (56624997).

Almost surely, 2113249993 is an apocalyptic number.

It is an amenable number.

113249993 is a deficient number, since it is larger than the sum of its proper divisors (1).

113249993 is an equidigital number, since it uses as much as digits as its factorization.

113249993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 52488, while the sum is 41.

The square root of 113249993 is about 10641.8979980077. The cubic root of 113249993 is about 483.8150731834.

The spelling of 113249993 in words is "one hundred thirteen million, two hundred forty-nine thousand, nine hundred ninety-three".