Base | Representation |
---|---|
bin | 110100101111001001… |
… | …1011100110010100101 |
3 | 101211022200022110122022 |
4 | 1221132103130302211 |
5 | 3323414313303121 |
6 | 124005452312525 |
7 | 11116321136423 |
oct | 1513623346245 |
9 | 354280273568 |
10 | 113251306661 |
11 | 44036456a09 |
12 | 19b47772745 |
13 | a8aac907bc |
14 | 56a4d26113 |
15 | 2e2c77caab |
hex | 1a5e4dcca5 |
113251306661 has 2 divisors, whose sum is σ = 113251306662. Its totient is φ = 113251306660.
The previous prime is 113251306591. The next prime is 113251306669. The reversal of 113251306661 is 166603152311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 104400072100 + 8851234561 = 323110^2 + 94081^2 .
It is a cyclic number.
It is not a de Polignac number, because 113251306661 - 210 = 113251305637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113251306669) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56625653330 + 56625653331.
It is an arithmetic number, because the mean of its divisors is an integer number (56625653331).
Almost surely, 2113251306661 is an apocalyptic number.
It is an amenable number.
113251306661 is a deficient number, since it is larger than the sum of its proper divisors (1).
113251306661 is an equidigital number, since it uses as much as digits as its factorization.
113251306661 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 35.
Adding to 113251306661 its reverse (166603152311), we get a palindrome (279854458972).
The spelling of 113251306661 in words is "one hundred thirteen billion, two hundred fifty-one million, three hundred six thousand, six hundred sixty-one".
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