113251353413053 has 2 divisors, whose sum is σ = 113251353413054. Its totient is φ = 113251353413052.

The previous prime is 113251353412999. The next prime is 113251353413057. The reversal of 113251353413053 is 350314353152311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78240428911044 + 35010924502009 = 8845362^2 + 5917003^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113251353413053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113251353412997 and 113251353413015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113251353413057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56625676706526 + 56625676706527.

It is an arithmetic number, because the mean of its divisors is an integer number (56625676706527).

Almost surely, 2^{113251353413053} is an apocalyptic number.

It is an amenable number.

113251353413053 is a deficient number, since it is larger than the sum of its proper divisors (1).

113251353413053 is an equidigital number, since it uses as much as digits as its factorization.

113251353413053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243000, while the sum is 40.

The spelling of 113251353413053 in words is "one hundred thirteen trillion, two hundred fifty-one billion, three hundred fifty-three million, four hundred thirteen thousand, fifty-three".