11325141434543 has 4 divisors (see below), whose sum is σ = 11325151539000. Its totient is φ = 11325131330088.

The previous prime is 11325141434531. The next prime is 11325141434587. The reversal of 11325141434543 is 34543414152311.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11325141434543 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11325141434543.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11325141434143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3126293 + ... + 5694206.

It is an arithmetic number, because the mean of its divisors is an integer number (2831287884750).

Almost surely, 2^{11325141434543} is an apocalyptic number.

11325141434543 is a deficient number, since it is larger than the sum of its proper divisors (10104457).

11325141434543 is an equidigital number, since it uses as much as digits as its factorization.

11325141434543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10104456.

The product of its digits is 345600, while the sum is 41.

Adding to 11325141434543 its reverse (34543414152311), we get a palindrome (45868555586854).

The spelling of 11325141434543 in words is "eleven trillion, three hundred twenty-five billion, one hundred forty-one million, four hundred thirty-four thousand, five hundred forty-three".