1132514533141 has 2 divisors, whose sum is σ = 1132514533142. Its totient is φ = 1132514533140.

The previous prime is 1132514533127. The next prime is 1132514533231. The reversal of 1132514533141 is 1413354152311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1011442547025 + 121071986116 = 1005705^2 + 347954^2 .

It is an emirp because it is prime and its reverse (1413354152311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1132514533141 - 2¹³ = 1132514524949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1132514533097 and 1132514533106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1132514536141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566257266570 + 566257266571.

It is an arithmetic number, because the mean of its divisors is an integer number (566257266571).

Almost surely, 2^{1132514533141} is an apocalyptic number.

It is an amenable number.

1132514533141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1132514533141 is an equidigital number, since it uses as much as digits as its factorization.

1132514533141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 21600, while the sum is 34.

Adding to 1132514533141 its reverse (1413354152311), we get a palindrome (2545868685452).

The spelling of 1132514533141 in words is "one trillion, one hundred thirty-two billion, five hundred fourteen million, five hundred thirty-three thousand, one hundred forty-one".