113252344435 has 4 divisors (see below), whose sum is σ = 135902813328. Its totient is φ = 90601875544.

The previous prime is 113252344397. The next prime is 113252344451. The reversal of 113252344435 is 534443252311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113252344435 - 2⁹ = 113252343923 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113252344394 and 113252344403.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11325234439 + ... + 11325234448.

It is an arithmetic number, because the mean of its divisors is an integer number (33975703332).

Almost surely, 2^113252344435 is an apocalyptic number.

113252344435 is a deficient number, since it is larger than the sum of its proper divisors (22650468893).

113252344435 is an equidigital number, since it uses as much as digits as its factorization.

113252344435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22650468892.

The product of its digits is 172800, while the sum is 37.

Adding to 113252344435 its reverse (534443252311), we get a palindrome (647695596746).

The spelling of 113252344435 in words is "one hundred thirteen billion, two hundred fifty-two million, three hundred forty-four thousand, four hundred thirty-five".