Base | Representation |
---|---|
bin | 110100101111001101… |
… | …0011010010001010001 |
3 | 101211022210202011122012 |
4 | 1221132122122101101 |
5 | 3323420300200340 |
6 | 124005555352305 |
7 | 11116342506254 |
oct | 1513632322121 |
9 | 354283664565 |
10 | 113253131345 |
11 | 44037492912 |
12 | 19b482b2695 |
13 | a8ab47c1b3 |
14 | 56a527d09b |
15 | 2e2c9dd565 |
hex | 1a5e69a451 |
113253131345 has 4 divisors (see below), whose sum is σ = 135903757620. Its totient is φ = 90602505072.
The previous prime is 113253131309. The next prime is 113253131353. The reversal of 113253131345 is 543131352311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 26110681744 + 87142449601 = 161588^2 + 295199^2 .
It is a cyclic number.
It is not a de Polignac number, because 113253131345 - 212 = 113253127249 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11325313130 + ... + 11325313139.
It is an arithmetic number, because the mean of its divisors is an integer number (33975939405).
Almost surely, 2113253131345 is an apocalyptic number.
It is an amenable number.
113253131345 is a deficient number, since it is larger than the sum of its proper divisors (22650626275).
113253131345 is an equidigital number, since it uses as much as digits as its factorization.
113253131345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22650626274.
The product of its digits is 16200, while the sum is 32.
Adding to 113253131345 its reverse (543131352311), we get a palindrome (656384483656).
The spelling of 113253131345 in words is "one hundred thirteen billion, two hundred fifty-three million, one hundred thirty-one thousand, three hundred forty-five".
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