Base | Representation |
---|---|
bin | 110100101111001101… |
… | …1100100010101011001 |
3 | 101211022211022120210001 |
4 | 1221132123210111121 |
5 | 3323420334402323 |
6 | 124010010053001 |
7 | 11116345211566 |
oct | 1513633442531 |
9 | 354284276701 |
10 | 113253434713 |
11 | 4403767a831 |
12 | 19b4841a161 |
13 | a8ab5572c3 |
14 | 56a531b86d |
15 | 2e2ca4d3ad |
hex | 1a5e6e4559 |
113253434713 has 2 divisors, whose sum is σ = 113253434714. Its totient is φ = 113253434712.
The previous prime is 113253434711. The next prime is 113253434779. The reversal of 113253434713 is 317434352311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 112833512649 + 419922064 = 335907^2 + 20492^2 .
It is an emirp because it is prime and its reverse (317434352311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113253434713 - 21 = 113253434711 is a prime.
Together with 113253434711, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (113253434711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56626717356 + 56626717357.
It is an arithmetic number, because the mean of its divisors is an integer number (56626717357).
Almost surely, 2113253434713 is an apocalyptic number.
It is an amenable number.
113253434713 is a deficient number, since it is larger than the sum of its proper divisors (1).
113253434713 is an equidigital number, since it uses as much as digits as its factorization.
113253434713 is an evil number, because the sum of its binary digits is even.
The product of its digits is 90720, while the sum is 37.
The spelling of 113253434713 in words is "one hundred thirteen billion, two hundred fifty-three million, four hundred thirty-four thousand, seven hundred thirteen".
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