Base | Representation |
---|---|
bin | 110100101111001111… |
… | …1010001000100000001 |
3 | 101211022220010211212122 |
4 | 1221132133101010001 |
5 | 3323421111414403 |
6 | 124010042534025 |
7 | 11116356360536 |
oct | 1513637210401 |
9 | 354286124778 |
10 | 113254404353 |
11 | 44038182292 |
12 | 19b48807315 |
13 | a8ab80675c |
14 | 56a54d0d8d |
15 | 2e2cb90838 |
hex | 1a5e7d1101 |
113254404353 has 2 divisors, whose sum is σ = 113254404354. Its totient is φ = 113254404352.
The previous prime is 113254404343. The next prime is 113254404371. The reversal of 113254404353 is 353404452311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 86713758784 + 26540645569 = 294472^2 + 162913^2 .
It is a cyclic number.
It is not a de Polignac number, because 113254404353 - 210 = 113254403329 is a prime.
It is not a weakly prime, because it can be changed into another prime (113254404343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56627202176 + 56627202177.
It is an arithmetic number, because the mean of its divisors is an integer number (56627202177).
Almost surely, 2113254404353 is an apocalyptic number.
It is an amenable number.
113254404353 is a deficient number, since it is larger than the sum of its proper divisors (1).
113254404353 is an equidigital number, since it uses as much as digits as its factorization.
113254404353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 113254404353 its reverse (353404452311), we get a palindrome (466658856664).
The spelling of 113254404353 in words is "one hundred thirteen billion, two hundred fifty-four million, four hundred four thousand, three hundred fifty-three".
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