Base | Representation |
---|---|
bin | 11001110000000100011110… |
… | …110110110110010101001111 |
3 | 112212000000200112220001201022 |
4 | 121300010132312312111033 |
5 | 104321030214120314043 |
6 | 1040512223114504355 |
7 | 32566240226030336 |
oct | 3160043666662517 |
9 | 485000615801638 |
10 | 113254510323023 |
11 | 330a4a715a1603 |
12 | 108515964350bb |
13 | 4b26b1543c624 |
14 | 1dd7794680d1d |
15 | d16022bec868 |
hex | 67011edb654f |
113254510323023 has 2 divisors, whose sum is σ = 113254510323024. Its totient is φ = 113254510323022.
The previous prime is 113254510322977. The next prime is 113254510323067. The reversal of 113254510323023 is 320323015452311.
It is a strong prime.
It is an emirp because it is prime and its reverse (320323015452311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113254510323023 - 216 = 113254510257487 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113254510323623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56627255161511 + 56627255161512.
It is an arithmetic number, because the mean of its divisors is an integer number (56627255161512).
Almost surely, 2113254510323023 is an apocalyptic number.
113254510323023 is a deficient number, since it is larger than the sum of its proper divisors (1).
113254510323023 is an equidigital number, since it uses as much as digits as its factorization.
113254510323023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 113254510323023 its reverse (320323015452311), we get a palindrome (433577525775334).
The spelling of 113254510323023 in words is "one hundred thirteen trillion, two hundred fifty-four billion, five hundred ten million, three hundred twenty-three thousand, twenty-three".
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