113256203441 has 4 divisors (see below), whose sum is σ = 113300953584. Its totient is φ = 113211453300.

The previous prime is 113256203407. The next prime is 113256203443. The reversal of 113256203441 is 144302652311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 144302652311 = 61 ⋅2365617251.

It is a cyclic number.

It is not a de Polignac number, because 113256203441 - 2¹⁰ = 113256202417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113256203398 and 113256203407.

It is not an unprimeable number, because it can be changed into a prime (113256203443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22371275 + ... + 22376336.

It is an arithmetic number, because the mean of its divisors is an integer number (28325238396).

Almost surely, 2^113256203441 is an apocalyptic number.

It is an amenable number.

113256203441 is a deficient number, since it is larger than the sum of its proper divisors (44750143).

113256203441 is an equidigital number, since it uses as much as digits as its factorization.

113256203441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44750142.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 113256203441 its reverse (144302652311), we get a palindrome (257558855752).

The spelling of 113256203441 in words is "one hundred thirteen billion, two hundred fifty-six million, two hundred three thousand, four hundred forty-one".