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113260131155 = 522652026231
BaseRepresentation
bin110100101111011010…
…1000111001101010011
3101211100021220210120102
41221132311013031103
53323424043144110
6124010405403015
711116456142003
oct1513665071523
9354307823512
10113260131155
1144040433986
1219b4a70946b
13a8aca602b2
1456a6182003
152e2d4225a5
hex1a5ed47353

113260131155 has 4 divisors (see below), whose sum is σ = 135912157392. Its totient is φ = 90608104920.

The previous prime is 113260131151. The next prime is 113260131157. The reversal of 113260131155 is 551131062311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 551131062311 = 1638133644531.

It is not a de Polignac number, because 113260131155 - 22 = 113260131151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113260131151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11326013111 + ... + 11326013120.

It is an arithmetic number, because the mean of its divisors is an integer number (33978039348).

Almost surely, 2113260131155 is an apocalyptic number.

113260131155 is a deficient number, since it is larger than the sum of its proper divisors (22652026237).

113260131155 is an equidigital number, since it uses as much as digits as its factorization.

113260131155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22652026236.

The product of its (nonzero) digits is 2700, while the sum is 29.

Adding to 113260131155 its reverse (551131062311), we get a palindrome (664391193466).

The spelling of 113260131155 in words is "one hundred thirteen billion, two hundred sixty million, one hundred thirty-one thousand, one hundred fifty-five".

Divisors: 1 5 22652026231 113260131155