Base | Representation |
---|---|
bin | 110100101111011100… |
… | …1101010111111101011 |
3 | 101211100101011112000121 |
4 | 1221132321222333223 |
5 | 3323424344420230 |
6 | 124010451144111 |
7 | 11116502250304 |
oct | 1513671527753 |
9 | 354311145017 |
10 | 113261326315 |
11 | 4404107a915 |
12 | 19b4aba5037 |
13 | a8b008b2a7 |
14 | 56a63b37ab |
15 | 2e2d5ab77a |
hex | 1a5ee6afeb |
113261326315 has 4 divisors (see below), whose sum is σ = 135913591584. Its totient is φ = 90609061048.
The previous prime is 113261326313. The next prime is 113261326361. The reversal of 113261326315 is 513623162311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113261326315 - 21 = 113261326313 is a prime.
It is a super-2 number, since 2×1132613263152 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113261326313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11326132627 + ... + 11326132636.
It is an arithmetic number, because the mean of its divisors is an integer number (33978397896).
Almost surely, 2113261326315 is an apocalyptic number.
113261326315 is a deficient number, since it is larger than the sum of its proper divisors (22652265269).
113261326315 is an equidigital number, since it uses as much as digits as its factorization.
113261326315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22652265268.
The product of its digits is 19440, while the sum is 34.
Adding to 113261326315 its reverse (513623162311), we get a palindrome (626884488626).
The spelling of 113261326315 in words is "one hundred thirteen billion, two hundred sixty-one million, three hundred twenty-six thousand, three hundred fifteen".
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