Base | Representation |
---|---|
bin | 11001110000010011111110… |
… | …010000010100001100100100 |
3 | 112212001121121201121202221211 |
4 | 121300103332100110030210 |
5 | 104321313300131020004 |
6 | 1040524013403321204 |
7 | 32600366344232350 |
oct | 3160237620241444 |
9 | 485047551552854 |
10 | 113271143220004 |
11 | 33101027414260 |
12 | 10854858820204 |
13 | 4b2856636bbc3 |
14 | 1dd84d16c0460 |
15 | d1669805d504 |
hex | 6704fe414324 |
113271143220004 has 48 divisors (see below), whose sum is σ = 253164772457856. Its totient is φ = 43055233401600.
The previous prime is 113271143219957. The next prime is 113271143220047. The reversal of 113271143220004 is 400022341172311.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4484907519 + ... + 4484932774.
It is an arithmetic number, because the mean of its divisors is an integer number (5274266092872).
Almost surely, 2113271143220004 is an apocalyptic number.
113271143220004 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
113271143220004 is an abundant number, since it is smaller than the sum of its proper divisors (139893629237852).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113271143220004 is a wasteful number, since it uses less digits than its factorization.
113271143220004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8969840356 (or 8969840354 counting only the distinct ones).
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 113271143220004 its reverse (400022341172311), we get a palindrome (513293484392315).
The spelling of 113271143220004 in words is "one hundred thirteen trillion, two hundred seventy-one billion, one hundred forty-three million, two hundred twenty thousand, four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •