Base | Representation |
---|---|
bin | 110100101111111111… |
… | …0011110111100011101 |
3 | 101211101122002222022002 |
4 | 1221133332132330131 |
5 | 3323444004134033 |
6 | 124012333532045 |
7 | 11120111500022 |
oct | 1513776367435 |
9 | 354348088262 |
10 | 113279364893 |
11 | 44050280532 |
12 | 19b55044025 |
13 | a8b3a359c6 |
14 | 56a894b549 |
15 | 2e2ee713e8 |
hex | 1a5ff9ef1d |
113279364893 has 2 divisors, whose sum is σ = 113279364894. Its totient is φ = 113279364892.
The previous prime is 113279364883. The next prime is 113279364907. The reversal of 113279364893 is 398463972311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 108661211044 + 4618153849 = 329638^2 + 67957^2 .
It is a cyclic number.
It is not a de Polignac number, because 113279364893 - 230 = 112205623069 is a prime.
It is a super-2 number, since 2×1132793648932 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113279364823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56639682446 + 56639682447.
It is an arithmetic number, because the mean of its divisors is an integer number (56639682447).
Almost surely, 2113279364893 is an apocalyptic number.
It is an amenable number.
113279364893 is a deficient number, since it is larger than the sum of its proper divisors (1).
113279364893 is an equidigital number, since it uses as much as digits as its factorization.
113279364893 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5878656, while the sum is 56.
The spelling of 113279364893 in words is "one hundred thirteen billion, two hundred seventy-nine million, three hundred sixty-four thousand, eight hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.096 sec. • engine limits •