Base | Representation |
---|---|
bin | 1010010011011111010111… |
… | …1111011110111111001111 |
3 | 1111010010121002202000010202 |
4 | 2210313311333132333033 |
5 | 2441112222142210341 |
6 | 40032524305524115 |
7 | 2246363603315432 |
oct | 244676577367717 |
9 | 44103532660122 |
10 | 11329955819471 |
11 | 3679009763803 |
12 | 132b9a334363b |
13 | 642544419413 |
14 | 2b2530d01819 |
15 | 149ab8b6679b |
hex | a4df5fdefcf |
11329955819471 has 2 divisors, whose sum is σ = 11329955819472. Its totient is φ = 11329955819470.
The previous prime is 11329955819461. The next prime is 11329955819509. The reversal of 11329955819471 is 17491855992311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11329955819471 - 26 = 11329955819407 is a prime.
It is a super-3 number, since 3×113299558194713 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11329955819398 and 11329955819407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11329955819461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5664977909735 + 5664977909736.
It is an arithmetic number, because the mean of its divisors is an integer number (5664977909736).
Almost surely, 211329955819471 is an apocalyptic number.
11329955819471 is a deficient number, since it is larger than the sum of its proper divisors (1).
11329955819471 is an equidigital number, since it uses as much as digits as its factorization.
11329955819471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 24494400, while the sum is 65.
The spelling of 11329955819471 in words is "eleven trillion, three hundred twenty-nine billion, nine hundred fifty-five million, eight hundred nineteen thousand, four hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •