11330012225041 has 2 divisors, whose sum is σ = 11330012225042. Its totient is φ = 11330012225040.

The previous prime is 11330012225023. The next prime is 11330012225047. The reversal of 11330012225041 is 14052221003311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10308780711441 + 1021231513600 = 3210729^2 + 1010560^2 .

It is a cyclic number.

It is not a de Polignac number, because 11330012225041 - 2¹⁹ = 11330011700753 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11330012224997 and 11330012225015.

It is not a weakly prime, because it can be changed into another prime (11330012225047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665006112520 + 5665006112521.

It is an arithmetic number, because the mean of its divisors is an integer number (5665006112521).

Almost surely, 2^{11330012225041} is an apocalyptic number.

It is an amenable number.

11330012225041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11330012225041 is an equidigital number, since it uses as much as digits as its factorization.

11330012225041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 11330012225041 its reverse (14052221003311), we get a palindrome (25382233228352).

The spelling of 11330012225041 in words is "eleven trillion, three hundred thirty billion, twelve million, two hundred twenty-five thousand, forty-one".