11330013100130 has 64 divisors (see below), whose sum is σ = 20968146984960. Its totient is φ = 4405255872000.

The previous prime is 11330013100103. The next prime is 11330013100139. The reversal of 11330013100130 is 3100131003311.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11330013100099 and 11330013100108.

It is not an unprimeable number, because it can be changed into a prime (11330013100139) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 169382252 + ... + 169449128.

It is an arithmetic number, because the mean of its divisors is an integer number (327627296640).

Almost surely, 2^{11330013100130} is an apocalyptic number.

11330013100130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11330013100130 is a deficient number, since it is larger than the sum of its proper divisors (9638133884830).

11330013100130 is a wasteful number, since it uses less digits than its factorization.

11330013100130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68435.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 11330013100130 its reverse (3100131003311), we get a palindrome (14430144103441).

The spelling of 11330013100130 in words is "eleven trillion, three hundred thirty billion, thirteen million, one hundred thousand, one hundred thirty".