113301002113 has 4 divisors (see below), whose sum is σ = 122016463828. Its totient is φ = 104585540400.

The previous prime is 113301002069. The next prime is 113301002123. The reversal of 113301002113 is 311200103311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 76777205569 + 36523796544 = 277087^2 + 191112^2 .

It is a cyclic number.

It is not a de Polignac number, because 113301002113 - 2³³ = 104711067521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113301002123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4357730838 + ... + 4357730863.

It is an arithmetic number, because the mean of its divisors is an integer number (30504115957).

Almost surely, 2^113301002113 is an apocalyptic number.

113301002113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

113301002113 is a deficient number, since it is larger than the sum of its proper divisors (8715461715).

113301002113 is an equidigital number, since it uses as much as digits as its factorization.

113301002113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8715461714.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 113301002113 its reverse (311200103311), we get a palindrome (424501105424).

The spelling of 113301002113 in words is "one hundred thirteen billion, three hundred one million, two thousand, one hundred thirteen".