Base | Representation |
---|---|
bin | 110100110000101000… |
… | …1000001011110001100 |
3 | 101211110010211021000000 |
4 | 1221201101001132030 |
5 | 3324020024031444 |
6 | 124014425404300 |
7 | 11120463425232 |
oct | 1514121013614 |
9 | 354403737000 |
10 | 113301002124 |
11 | 44061509942 |
12 | 19b60339690 |
13 | a8b83703bb |
14 | 56ab780952 |
15 | 2e31ce7469 |
hex | 1a6144178c |
113301002124 has 84 divisors (see below), whose sum is σ = 298837042560. Its totient is φ = 37569083040.
The previous prime is 113301002123. The next prime is 113301002131. The reversal of 113301002124 is 421200103311.
It is a super-2 number, since 2×1133010021242 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 113301002097 and 113301002106.
It is not an unprimeable number, because it can be changed into a prime (113301002123) by changing a digit.
It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 455242 + ... + 658670.
It is an arithmetic number, because the mean of its divisors is an integer number (3557583840).
Almost surely, 2113301002124 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 113301002124, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (149418521280).
113301002124 is an abundant number, since it is smaller than the sum of its proper divisors (185536040436).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113301002124 is a wasteful number, since it uses less digits than its factorization.
113301002124 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 203642 (or 203625 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 113301002124 its reverse (421200103311), we get a palindrome (534501105435).
The spelling of 113301002124 in words is "one hundred thirteen billion, three hundred one million, two thousand, one hundred twenty-four".
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