1133011101331 has 4 divisors (see below), whose sum is σ = 1199658813192. Its totient is φ = 1066363389472.

The previous prime is 1133011101323. The next prime is 1133011101361. The reversal of 1133011101331 is 1331011103311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1133011101331 - 2³ = 1133011101323 is a prime.

It is a super-2 number, since 2×1133011101331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1133011101299 and 1133011101308.

It is not an unprimeable number, because it can be changed into a prime (1133011101301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33323855905 + ... + 33323855938.

It is an arithmetic number, because the mean of its divisors is an integer number (299914703298).

Almost surely, 2^{1133011101331} is an apocalyptic number.

1133011101331 is a deficient number, since it is larger than the sum of its proper divisors (66647711861).

1133011101331 is an equidigital number, since it uses as much as digits as its factorization.

1133011101331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66647711860.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 1133011101331 its reverse (1331011103311), we get a palindrome (2464022204642).

The spelling of 1133011101331 in words is "one trillion, one hundred thirty-three billion, eleven million, one hundred one thousand, three hundred thirty-one".