Base | Representation |
---|---|
bin | 10101000110101001… |
… | …11110100101001101 |
3 | 1002020121121201202120 |
4 | 22203110332211031 |
5 | 141201002320023 |
6 | 5112135443153 |
7 | 550525300602 |
oct | 124324764515 |
9 | 32217551676 |
10 | 11330120013 |
11 | 4894614953 |
12 | 22425264b9 |
13 | 10b743cc34 |
14 | 796a846a9 |
15 | 464a4c8e3 |
hex | 2a353e94d |
11330120013 has 4 divisors (see below), whose sum is σ = 15106826688. Its totient is φ = 7553413340.
The previous prime is 11330119993. The next prime is 11330120029. The reversal of 11330120013 is 31002103311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11330120013 - 25 = 11330119981 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11330119974 and 11330120001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11330120083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1888353333 + ... + 1888353338.
It is an arithmetic number, because the mean of its divisors is an integer number (3776706672).
Almost surely, 211330120013 is an apocalyptic number.
It is an amenable number.
11330120013 is a deficient number, since it is larger than the sum of its proper divisors (3776706675).
11330120013 is an equidigital number, since it uses as much as digits as its factorization.
11330120013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3776706674.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 11330120013 its reverse (31002103311), we get a palindrome (42332223324).
The spelling of 11330120013 in words is "eleven billion, three hundred thirty million, one hundred twenty thousand, thirteen".
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