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1133012013 = 3753952953
BaseRepresentation
bin100001110001000…
…0110010000101101
32220221221222021220
41003202012100231
54310022341023
6304232213553
740035305010
oct10342062055
92827858256
101133012013
11531612771
1227753a2b9
1315096b913
14aa693377
15697073e3
hex4388642d

1133012013 has 8 divisors (see below), whose sum is σ = 1726494528. Its totient is φ = 647435424.

The previous prime is 1133012011. The next prime is 1133012017. The reversal of 1133012013 is 3102103311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1133012013 - 21 = 1133012011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1133011983 and 1133012001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1133012011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26976456 + ... + 26976497.

It is an arithmetic number, because the mean of its divisors is an integer number (215811816).

Almost surely, 21133012013 is an apocalyptic number.

It is an amenable number.

1133012013 is a deficient number, since it is larger than the sum of its proper divisors (593482515).

1133012013 is an equidigital number, since it uses as much as digits as its factorization.

1133012013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53952963.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 1133012013 is about 33660.2438048211. The cubic root of 1133012013 is about 1042.5050598700.

Adding to 1133012013 its reverse (3102103311), we get a palindrome (4235115324).

The spelling of 1133012013 in words is "one billion, one hundred thirty-three million, twelve thousand, thirteen".

Divisors: 1 3 7 21 53952953 161858859 377670671 1133012013