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11330323230893 is a prime number
BaseRepresentation
bin1010010011100000101111…
…1001000011000010101101
31111010011112201002102212012
42210320023321003002231
52441114000221342033
640033024552451005
72246405654260652
oct244701371030255
944104481072765
1011330323230893
1136791880a0407
12132ba863a9a65
136425a258a724
142b2567a21c29
15149adb03e248
hexa4e0be430ad

11330323230893 has 2 divisors, whose sum is σ = 11330323230894. Its totient is φ = 11330323230892.

The previous prime is 11330323230791. The next prime is 11330323230907. The reversal of 11330323230893 is 39803232303311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10862047160644 + 468276070249 = 3295762^2 + 684307^2 .

It is an emirp because it is prime and its reverse (39803232303311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11330323230893 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11330323230893.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11330323280893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665161615446 + 5665161615447.

It is an arithmetic number, because the mean of its divisors is an integer number (5665161615447).

Almost surely, 211330323230893 is an apocalyptic number.

It is an amenable number.

11330323230893 is a deficient number, since it is larger than the sum of its proper divisors (1).

11330323230893 is an equidigital number, since it uses as much as digits as its factorization.

11330323230893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 209952, while the sum is 41.

The spelling of 11330323230893 in words is "eleven trillion, three hundred thirty billion, three hundred twenty-three million, two hundred thirty thousand, eight hundred ninety-three".