1133043344341 has 2 divisors, whose sum is σ = 1133043344342. Its totient is φ = 1133043344340.

The previous prime is 1133043344317. The next prime is 1133043344453. The reversal of 1133043344341 is 1434433403311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1104504310116 + 28539034225 = 1050954^2 + 168935^2 .

It is an emirp because it is prime and its reverse (1434433403311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1133043344341 - 2¹⁵ = 1133043311573 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1133043344297 and 1133043344306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1133043344311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566521672170 + 566521672171.

It is an arithmetic number, because the mean of its divisors is an integer number (566521672171).

Almost surely, 2^{1133043344341} is an apocalyptic number.

It is an amenable number.

1133043344341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133043344341 is an equidigital number, since it uses as much as digits as its factorization.

1133043344341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 1133043344341 its reverse (1434433403311), we get a palindrome (2567476747652).

The spelling of 1133043344341 in words is "one trillion, one hundred thirty-three billion, forty-three million, three hundred forty-four thousand, three hundred forty-one".