Base | Representation |
---|---|
bin | 1010010011100011010011… |
… | …1000101110100110001010 |
3 | 1111010020022122021101112122 |
4 | 2210320310320232212022 |
5 | 2441121402304404002 |
6 | 40033221122211242 |
7 | 2246432005314422 |
oct | 244706470564612 |
9 | 44106278241478 |
10 | 11331011013002 |
11 | 367950035527a |
12 | 13300387b3b22 |
13 | 642681c0c8a5 |
14 | 2b25d10d9482 |
15 | 149b2b5eb6a2 |
hex | a4e34e2e98a |
11331011013002 has 4 divisors (see below), whose sum is σ = 16996516519506. Its totient is φ = 5665505506500.
The previous prime is 11331011012963. The next prime is 11331011013011. The reversal of 11331011013002 is 20031011013311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10444718685241 + 886292327761 = 3231829^2 + 941431^2 .
It is a super-2 number, since 2×113310110130022 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2832752753249 + ... + 2832752753252.
Almost surely, 211331011013002 is an apocalyptic number.
11331011013002 is a deficient number, since it is larger than the sum of its proper divisors (5665505506504).
11331011013002 is an equidigital number, since it uses as much as digits as its factorization.
11331011013002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5665505506503.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11331011013002 its reverse (20031011013311), we get a palindrome (31362022026313).
The spelling of 11331011013002 in words is "eleven trillion, three hundred thirty-one billion, eleven million, thirteen thousand, two".
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