Base | Representation |
---|---|
bin | 1010010011100011010110… |
… | …0011000100110111111111 |
3 | 1111010020100102011101122221 |
4 | 2210320311203010313333 |
5 | 2441121413130124203 |
6 | 40033222200150211 |
7 | 2246432201551633 |
oct | 244706543046777 |
9 | 44106312141587 |
10 | 11331022114303 |
11 | 3679506647901 |
12 | 1330040468367 |
13 | 6426842c87c8 |
14 | 2b25d2788dc3 |
15 | 149b2c590abd |
hex | a4e358c4dff |
11331022114303 has 2 divisors, whose sum is σ = 11331022114304. Its totient is φ = 11331022114302.
The previous prime is 11331022114261. The next prime is 11331022114309. The reversal of 11331022114303 is 30341122013311.
It is a strong prime.
It is an emirp because it is prime and its reverse (30341122013311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11331022114303 - 229 = 11330485243391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331022114309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665511057151 + 5665511057152.
It is an arithmetic number, because the mean of its divisors is an integer number (5665511057152).
Almost surely, 211331022114303 is an apocalyptic number.
11331022114303 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331022114303 is an equidigital number, since it uses as much as digits as its factorization.
11331022114303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 11331022114303 its reverse (30341122013311), we get a palindrome (41672144127614).
The spelling of 11331022114303 in words is "eleven trillion, three hundred thirty-one billion, twenty-two million, one hundred fourteen thousand, three hundred three".
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