11331023000131 has 4 divisors (see below), whose sum is σ = 11721747931200. Its totient is φ = 10940298069064.

The previous prime is 11331023000119. The next prime is 11331023000161. The reversal of 11331023000131 is 13100032013311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11331023000131 - 2²³ = 11331014611523 is a prime.

It is a super-3 number, since 3×11331023000131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11331023000099 and 11331023000108.

It is not an unprimeable number, because it can be changed into a prime (11331023000161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195362465491 + ... + 195362465548.

It is an arithmetic number, because the mean of its divisors is an integer number (2930436982800).

Almost surely, 2^{11331023000131} is an apocalyptic number.

11331023000131 is a deficient number, since it is larger than the sum of its proper divisors (390724931069).

11331023000131 is an equidigital number, since it uses as much as digits as its factorization.

11331023000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 390724931068.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11331023000131 its reverse (13100032013311), we get a palindrome (24431055013442).

The spelling of 11331023000131 in words is "eleven trillion, three hundred thirty-one billion, twenty-three million, one hundred thirty-one", and thus it is an aban number.