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113310231997 is a prime number
BaseRepresentation
bin110100110000111010…
…0001110110110111101
3101211110210012012000011
41221201310032312331
53324024404410442
6124015355303221
711120635036414
oct1514164166675
9354423165004
10113310231997
1144066743436
1219b6344ab11
13a8ba252571
1456acaa447b
152e32a1c117
hex1a61d0edbd

113310231997 has 2 divisors, whose sum is σ = 113310231998. Its totient is φ = 113310231996.

The previous prime is 113310231967. The next prime is 113310232003. The reversal of 113310231997 is 799132013311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113222828196 + 87403801 = 336486^2 + 9349^2 .

It is an emirp because it is prime and its reverse (799132013311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113310231997 - 227 = 113176014269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113310231967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56655115998 + 56655115999.

It is an arithmetic number, because the mean of its divisors is an integer number (56655115999).

Almost surely, 2113310231997 is an apocalyptic number.

It is an amenable number.

113310231997 is a deficient number, since it is larger than the sum of its proper divisors (1).

113310231997 is an equidigital number, since it uses as much as digits as its factorization.

113310231997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30618, while the sum is 40.

The spelling of 113310231997 in words is "one hundred thirteen billion, three hundred ten million, two hundred thirty-one thousand, nine hundred ninety-seven".