Base | Representation |
---|---|
bin | 1010010011100011011000… |
… | …1101111101001100100111 |
3 | 1111010020101012022111001210 |
4 | 2210320312031331030213 |
5 | 2441121424014330142 |
6 | 40033223241122503 |
7 | 2246432366236530 |
oct | 244706615751447 |
9 | 44106335274053 |
10 | 11331033355047 |
11 | 3679511a2517a |
12 | 1330044189433 |
13 | 642686733033 |
14 | 2b25d4073687 |
15 | 149b2d56149c |
hex | a4e3637d327 |
11331033355047 has 32 divisors (see below), whose sum is σ = 17745911465472. Its totient is φ = 6295290551424.
The previous prime is 11331033355027. The next prime is 11331033355051. The reversal of 11331033355047 is 74055333013311.
It is not a de Polignac number, because 11331033355047 - 28 = 11331033354791 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11331033354996 and 11331033355014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331033355027) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4243833 + ... + 6377474.
It is an arithmetic number, because the mean of its divisors is an integer number (554559733296).
Almost surely, 211331033355047 is an apocalyptic number.
11331033355047 is a deficient number, since it is larger than the sum of its proper divisors (6414878110425).
11331033355047 is a wasteful number, since it uses less digits than its factorization.
11331033355047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10622727.
The product of its (nonzero) digits is 170100, while the sum is 39.
Adding to 11331033355047 its reverse (74055333013311), we get a palindrome (85386366368358).
The spelling of 11331033355047 in words is "eleven trillion, three hundred thirty-one billion, thirty-three million, three hundred fifty-five thousand, forty-seven".
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